A) \[0.02\text{ }kg-{{m}^{2}}\]
B) \[0.002\text{ }kg-{{m}^{2}}\]
C) \[0.2\text{ }kg-{{m}^{2}}\]
D) \[2\text{ }kg-{{m}^{2}}\]
Correct Answer: C
Solution :
The moment of inertia of a disc of radius R about an axis perpendicular to the disc and passing through the centre is given by \[I=\frac{1}{2}M{{R}^{2}}\] \[=\frac{1}{2}\times 0.4\times {{1}^{2}}=0.2Kg{{m}^{2}}\]
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