A) \[s{{p}^{2}}-\]hybridised
B) \[s{{p}^{3}}d-\]hybridized
C) \[sp\]-hybridised
D) \[s{{p}^{3}}-\]hybridised.
Correct Answer: C
Solution :
\[{{C}_{ached\text{ }state}}=2{{s}^{1}}2{{p}_{x}}^{1}{{p}_{y}}^{1}{{p}_{z}}^{1}\] \[{{O}_{ground\text{ }state}}=2{{s}^{2}}2{{p}_{x}}^{2}{{p}_{y}}^{1}{{p}_{z}}^{1}\] In the formation of \[C{{O}_{2}}\] molecule, hybridization of orbitals of carbon occurs only to a limited extent involving only one s and one p orbital and gives rise to \[sp\] hybridization.
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