A) \[5.025\times {{10}^{23}}g\]
B) \[16.023\times {{10}^{23}}g\]
C) \[2.371\times {{10}^{-7}}\]
D) \[3.817\times {{10}^{-8}}\].
Correct Answer: C
Solution :
Molecular weight of \[{{C}_{60}}{{H}_{122}}=60\times 12+1\times 12\]\[=842\] Weight of 1 mole of \[{{C}_{60}}{{H}_{122}}\] molecules = 842 g or Weight of \[6.023\times {{10}^{23}}\]molecules = 842 g \[\Rightarrow \] Weight of 1 molecule of \[{{C}_{60}}{{H}_{122}}=\frac{842}{6.023\times {{10}^{23}}}g\] \[=1.4\times {{10}^{-21}}g\]
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