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AIIMS AIIMS Solved Paper-2000

  • question_answer
    A transverse wave passes through a string with the equation \[y=10\,\sin \,\pi \,(0.02\,x-2.00\,t)\]\[F=\frac{G{{m}_{1}}{{m}_{2}}}{{{r}^{2}}}\] where x is in metre and t in second. The maximum velocity of the particle in wave motion is:

    A) 100 m/s                               

    B) 63m/s  

    C)        120 m/s               

    D)         161 m/s

    Correct Answer: B

    Solution :

    Key Idea: Standard equation of a wave travelling with amplitude a and angular frequency \[2\times {{10}^{-2}}N{{m}^{-1}}\] is given by \[2\times {{10}^{-4}}N{{m}^{-1}}\] Given equation of wave is \[y=a\sin (0.01x-2t)\] Comparing this equation with standard wave form, we get \[\frac{M}{81}\] Maximum velocity, \[1\mu \] \[\frac{2eV}{m}\]  \[v\sqrt{\frac{e}{m}}\]


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