A) \[3.5kJ/mol\]
B) \[4.6kJ/mol\]
C) \[5.3kJ/mol\]
D) \[6.4kJ/mol\]
Correct Answer: C
Solution :
Enthalpy of neutralization is denned as amount of heat liberated when one mole of a strong acid is completely neutralized by one mole of a strong base. Its value is less in case of weak acid or weak base because small amount of heat is utilized in ionising the weak acid/base. \[\Delta H\] for ionisation of \[C{{H}_{3}}COOH\] = Heat of neutralization for \[C{{H}_{3}}COOH-\] Heat of neutralization of strong acid \[=-50.6-(-55.9)kJ/mol\] \[=+\text{ }5.3kJ/mol\]You need to login to perform this action.
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