A) \[N{{a}_{2}}S\]
B) \[N{{a}_{2}}S{{O}_{4}}\]
C) \[N{{a}_{2}}S{{O}_{3}}\]
D) \[N{{a}_{2}}{{S}_{4}}{{O}_{6}}\]
Correct Answer: D
Solution :
Hypo and iodine react as below: \[2N{{a}_{2}}{{S}_{2}}{{O}_{3}}+{{I}_{2}}\xrightarrow[{}]{}N{{a}_{2}}{{S}_{4}}{{O}_{6}}+2NAI\] Hypo is used as a fixing agent in photography to remove unchanged silver bromide as complex ion.
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