A) 42.3 g
B) 24.3 g
C) 4.23 g
D) 2.43 g
Correct Answer: C
Solution :
Copper sulphate and potassium iodide react as follows: \[2CuS{{O}_{4}}.5{{H}_{2}}O+4KI\to \] \[2C{{u}_{2}}{{I}_{2}}+2{{K}_{2}}S{{O}_{4}}+{{I}_{2}}+10{{H}_{2}}O\] Mass of copper sulphate used \[=2(63+32+64+5\times 18)=498g\] Mass of \[{{I}_{2}}\] liberated \[=2\times 127=254\text{ }g\] \[\because \] 498 g of \[CuS{{O}_{4}}\] liberate \[{{I}_{2}}=254g\] \[\therefore \] 8.3 g of \[CuS{{O}_{4}}\] liberate \[{{I}_{2}}=\frac{254}{498}\times 8.3\] \[=4.32g\]
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