A) \[I=\frac{E}{R}=\frac{3}{30}=0.1A\]
B) \[U=\frac{{{q}_{1}}{{q}_{2}}}{4\pi {{\varepsilon }_{0}}}\left( \frac{1}{{{R}_{1}}}-\frac{1}{{{R}_{2}}} \right)\]
C) \[=9\times {{10}^{9}}\times 1\times {{10}^{-6}}\times {{10}^{-3}}\left( \frac{1}{1}-\frac{1}{10} \right)\]
D) \[=8.1J\]
Correct Answer: A
Solution :
Key Idea: Moment of momentum is angular momentum. According to Bohrs model of atom, electrons can revolve only in those orbits in which their angular momentum is an integral multiple of \[\therefore \] where h is Planck universal constant. If J is moment of momentum i.e., angular momentum then from Bohrs postulate, we have \[{{v}_{m}}=\sqrt{\frac{2G{{M}_{e}}\times 4}{{{R}_{e}}\times 81}}\] where n is an integer (= 1, 2,3...) called the principal quantum number of the orbit, In the second orbit n = 2, therefore \[\frac{{{v}_{e}}}{{{v}_{m}}}=\sqrt{\frac{{{M}_{e}}}{{{R}_{e}}}\times \frac{81{{R}_{e}}}{4{{M}_{e}}}}=\frac{9}{2}\]
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