question_answer

A light of intensity \[{{I}_{0}}\] passes through a material of thickness d, then the intensity will be:

A) \[\Rightarrow \]              

B)        \[\frac{1}{2}m{{v}^{2}}=eV\]     

C)        \[\Rightarrow \]

D)                        None of these

Correct Answer: A

Solution :

                Light passing through a material of thickness d is attenuated by absorption and scattering. The exponential law of absorption gives the relation as \[\frac{1}{9x}=\frac{1}{60R-x}\] where \[\Rightarrow \] is wavelength. Alternative: The option (b) and (c) are dimensionally incorrect while option (a) is dimensionally correct.