A) 12 m/s, 6 m/s
B) 12 m/s, 25 m/s
C) 6 m/s, 12 m/s
D) 8 m/s, 20 m/s
Correct Answer: C
Solution :
Key Idea: In a perfectly etastic collision the relative velocity remains unchanged in magnitude but is reversed in direction. Since collision is elastic momentum remains conserved, hence we have momentum before collision = moittentum after collision Initial, \[\Rightarrow \] ?(1) Final, \[v=\sqrt{\frac{2eV}{m}}\] ?(2) Equating Eqs. (1) and (2), we get \[=eV\] \[\Rightarrow \] \[\frac{1}{2}m{{v}^{2}}=eV\] ...(3) Since collision is elastic relative velocity remains unchanged in magnitude but is reversed in direction. \[\Rightarrow \] \[v=\sqrt{\frac{2eV}{m}}\] \[B=\frac{{{\mu }_{0}}}{4\pi }\frac{2\pi i}{a}\] ??(4) \[B=\frac{{{\mu }_{0}}}{4\pi }\frac{2\pi i}{a}\] \[\pi \] Solving Eqs. (3) and (4), we get \[\mu F\]
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