A) 100 m/s
B) 63m/s
C) 120 m/s
D) 161 m/s
Correct Answer: B
Solution :
Key Idea: Standard equation of a wave travelling with amplitude a and angular frequency \[2\times {{10}^{-2}}N{{m}^{-1}}\] is given by \[2\times {{10}^{-4}}N{{m}^{-1}}\] Given equation of wave is \[y=a\sin (0.01x-2t)\] Comparing this equation with standard wave form, we get \[\frac{M}{81}\] Maximum velocity, \[1\mu \] \[\frac{2eV}{m}\] \[v\sqrt{\frac{e}{m}}\]You need to login to perform this action.
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