question_answer

A body is released from the top of the tower metre high. It takes t second to reach d ground. Where is the body after t/2 second release?

A) At 3H/4 metre from the ground

B) At H/2 metre from the ground

C) H/6 metre from the ground

D) At H/4 metre from the ground

Correct Answer: A

Solution :

                Key Idea: Since the body is released from rest initial velocity \[16\mu F\]. From equation of motion, we have \[{{E}_{a}}\] where g is acceleration due to gravity. We gave \[l\] \[{{E}_{q}}\]  \[l,\] Height of body at time \[{{E}_{a}}\] is \[{{E}_{q}}\] Hence, height of body from the ground \[{{E}_{a}}=4{{E}_{q}}\]