A) \[9x=60R-x\]
B) \[\Rightarrow \]
C) \[x=6R\]
D) \[{{\lambda }_{m}}T=constant\]
Correct Answer: C
Solution :
Intensity of electric field at a point on the axis of dipole is given by \[a=10m,\omega =2\pi rad/s\] ?.(1) where p is dipole moment, Intensity of electric field at a point on the equatorial line of dipole is given by \[{{v}_{\max }}=a\omega \] ??(2) Dividing Eq. (1) by Eq. (2), we get \[\therefore \] \[{{v}_{\max }}=10\times 2\pi =20\pi =20\times \frac{22}{7}=63m/s\] \[P=\frac{1}{f}\]You need to login to perform this action.
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