A) -2 J
B) 3 J
C) 1 J
D) 2 J
Correct Answer: A
Solution :
Key Idea: In adiabatic expansion Q = 0. According to first law of thermodynamics \[\Delta U=Q-W\] where \[\frac{2eV}{m}\] is internal energy and W is work done. \[v\sqrt{\frac{e}{m}}\] \[\sqrt{\frac{3ev}{m}}\] (\[\sqrt{\frac{2ev}{m}}\]Q = 0), Thus, internal energy is decreased by the amount equivalent to the work done by the gas in expansion. Hence, work done on the gas is - 2 J.
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