AIIMS AIIMS Solved Paper-2000

  • question_answer
    Two cars A and B approach a stationary observer from opposite sides as shown in figure. Observer hears no beats. If the frequency of the horn of the car B is 504 Hz, the frequency of horn of car A will be :

    A) 529.2 Hz              

    B)        295.2 Hz                              

    C) 440.5 Hz              

    D)        none of these

    Correct Answer: A

    Solution :

                    Key Idea: The apparent frequency of the two cars should be equal for no beats. From Dopplers effect the apparent change in frequency of a wave that is perceived by stationary observer is \[n={{n}_{0}}\left( \frac{v}{v-{{v}_{s}}} \right)\] where v is speed of sound. Since observer is not hearing any beats the apparent frequency of the two cars should be equal. \[\therefore \]  \[n=n\] \[504\left( \frac{v}{v-30} \right)=n\left( \frac{v}{v-15} \right)\] \[\therefore \]  \[n=\frac{(330-15)\times 504}{(330-30)}\] \[=\frac{315\times 504}{300}=529.2Hz\]


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