A) 3 : 1
B) 4 : 9
C) 4 : 1
D) 1 : 9
Correct Answer: C
Solution :
We know that intensity is directly proportional to the square of amplitude, hence intensity \[{{10}^{5}}N/{{m}^{2}}\] \[\sqrt{200}m/s\] \[\sqrt{400}m/s\] \[\sqrt{500}m/s\] Resultant intensity at a point is given by \[\sqrt{800}m/s\] where \[mg{{R}_{e}}\] is phase difference Maximum intensity \[mg{{R}_{e}}\] \[mg{{R}_{e}}\] \[mg{{R}_{e}}\] ?..(1) Minimum intensity \[\sqrt{3}\] \[\frac{R}{2}\] \[4.1\times {{10}^{-5}}wb\] ??(2) Dividing Eq. (1) by Eq. (2), we get \[5.2\times {{10}^{-5}}wb\] Note: Maximum intensity is also known as constructive interference and minimum intensity is known as destructive interference.
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