A) \[3\times 96500\text{ }C\]
B) \[6\times 96500\text{ }C\]
C) \[0.3\text{ }F\]
D) \[0.6\text{ }F\]
Correct Answer: B
Solution :
\[\overset{+6}{\mathop{C{{r}_{2}}}}\,O_{7}^{2-}+6{{e}^{-}}\xrightarrow{{}}C{{r}^{3+}}\] one mole of \[C{{r}_{2}}O_{7}^{2-}\] require six electrons to convert to \[C{{r}^{3+}}\] \[\therefore \] charge required \[=6\times 96500C\] [\[\because \] one \[{{e}^{-}}=96500C\]]
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