2. Solved Papers
  3. AIIMS

AIIMS AIIMS Solved Paper-2000

  • question_answer
    \[A+2B\rightleftharpoons 2C+D\] initial concentration of B was 1.5 times that of A, but the equilibrium concentration of A and B are found to be equal. The equilibrium constant for the reaction is:

    A)  4                                            

    B)  8                            

    C)  12                         

    D)         16

    Correct Answer: A

    Solution :

    In the given equation \[\begin{matrix}    \text{A+2B} &  & \text{2C+D}  \\    \text{1}\text{.01}\text{.5} & {} & \text{ 00}\,\text{intial}\,\text{conc}\text{.}  \\    \text{(1-x)}\,\text{(1}\text{.5-2x)} & {} & \text{2x}\,\text{x}\,\text{final}\,\text{conc}\text{.}  \\ \end{matrix}\] At equilibrium \[[A]=[B]\] \[1-x=1.5-2x\] \[\Rightarrow \]  \[x\overset{\bullet }{\mathop{=}}\,0.5\] \[{{K}_{c}}\frac{{{[C]}^{2}}[D]}{[A]{{[B]}^{2}}}=\frac{{{(2x)}^{2}}(x)}{(1-x){{(1.5-2x)}^{2}}}\] \[=\frac{1\times 1\times 0.5}{0.5\times 0.5\times 0.5}=4\]


You need to login to perform this action.
You will be redirected in 3 sec spinner