AIIMS AIIMS Solved Paper-2000

  • question_answer
    During isothermal expansion of one mole of an Ideal gas from 10 atm to 1 atm at 273 K, the work done is [gas constant = 2 ]:

    A)  \[-895.8\text{ }cal\]     

    B)  \[-1172.6\text{ }cal\]

    C)                         \[-1381.8\text{ }cal~~~~\]

    D)         \[-1499.6\text{ }cal\]

    Correct Answer: C

    Solution :

    Work done in isothermal reversible expansion of an Ideal gas \[=-2.303nRT\,\log \frac{{{P}_{1}}}{P{{ & }_{2}}}\] \[n=1,R=2,\text{ }T=273+27=300\text{ }K\] \[{{p}_{1}}=10atm,\,{{p}_{2}}=1atm\] \[W=-2.303\times 1\times 2\times 300\text{ }log\frac{10}{1}\] \[=-1381.\text{ 8c}al\]              [\[\because \] log 10=1]


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