A) 32
B) 34
C) 36
D) 38
Correct Answer: D
Solution :
Elements having 1, 2 or 3 electron in its last shell act as metals. \[32=[Ar]4{{s}^{2}}3{{d}^{10}}4{{p}^{2}}\] (4 electron in last shell two in 4s and 2 in 4p) \[\Rightarrow \] non metal \[34=[Ar]4{{s}^{2}}3{{d}^{10}}4{{p}^{4}}\] (4 electron in last shell -2 in 4s and 4 in 4p\[\Rightarrow \] non metals \[36=[Ar]4{{s}^{2}}3{{d}^{10}}4{{p}^{6}}\] (8 electron in last shell 2 in 45 and 6 is 4p) \[\Rightarrow \] inert gas \[38=[Kr]5{{s}^{2}}\] (only 2 electron in last shell) \[\therefore \] metal
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