A) Streckers reaction
B) Sandmeyers reaction
C) Wolff-Kishner reaction
D) Stephens reaction
Correct Answer: B
Solution :
The reaction is as Sandmeyer reaction. Streckers reaction: \[\underset{Ethanol}{\mathop{C{{H}_{3}}CHO}}\,\xrightarrow[-{{H}_{2}}O]{NaCN/N{{H}_{4}}Cl}\underset{\begin{smallmatrix} | \\ N{{H}_{2}} \\ 2-a\min o\,propane\,nitrile \end{smallmatrix}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C\equiv N}}\,\] \[\overset{N{{H}_{2}}}{\mathop{\overset{|}{\mathop{\underset{\alpha -alanine}{\mathop{\xrightarrow{{{H}_{3}}{{O}^{+}}}C{{H}_{3}}-CH-COOH+NH_{4}^{+}}}\,}}\,}}\,\] Wolff Kishner reaction (Reduction): Stephens reduction reaction \[\underset{\begin{smallmatrix} Alkyl \\ cyanide \end{smallmatrix}}{\mathop{RCN}}\,\xrightarrow[\begin{smallmatrix} (H) \\ \operatorname{Re}duction \end{smallmatrix}]{SnC{{l}_{2}}/HCl}\underset{Aldehyde}{\mathop{RCHO}}\,+N{{H}_{3}}\]You need to login to perform this action.
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