A) \[10.5g\,mo{{l}^{-1}}\]
B) \[12.6\text{ }g\,mo{{l}^{-1}}\]
C) \[15.7\text{ }g\,mo{{l}^{-1}}\]
D) \[17.3\text{ }g\,mo{{l}^{-1}}\]
Correct Answer: D
Solution :
Mol. mass of solute (m) \[=\frac{1000\times {{K}_{b}}}{\Delta {{T}_{b}}}\times \frac{w}{W}\] \[{{K}_{b}}=0.6K.kg/mol\] \[w=3g;W=200mL,\] \[\Delta {{T}_{b}}={{100.52}^{o}}C-{{100}^{o}}C={{0.52}^{o}}C\] Putting the values we have \[=\frac{1000\times 0.6}{0.52}\times \frac{3}{200}=\frac{1800}{104}\] \[=17.307g/mol\]
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