A) \[HCHO~\]
B) \[C{{H}_{3}}CHO\]
C) \[C{{H}_{3}}C{{H}_{2}}CHO\]
D) \[C{{H}_{3}}COC{{H}_{3}}\]
Correct Answer: A
Solution :
Aldol condensation involves condensation reaction between two aldehyde molecules or two ketone molecules containing \[\alpha -H\] atom in the presence of dilute alkali. \[\underset{Ethanal}{\mathop{{{H}_{3}}C-\underset{H}{\overset{O}{\mathop{\underset{|}{\overset{||}{\mathop{C}}}\,}}}\,+HC{{H}_{2}}CHO\xrightarrow{dil.\,NaOH}}}\,\] \[\underset{Aldol}{\mathop{C{{H}_{3}}-\underset{H}{\overset{OH}{\mathop{\underset{|}{\overset{||}{\mathop{C}}}\,}}}\,+C{{H}_{2}}-CHO\xrightarrow[{{H}^{+}}]{\Delta }}}\,\] \[\underset{But-2-enal}{\mathop{C{{H}_{3}}CH=CHCHO}}\,\] \[\therefore \]compounds like \[HCHO,{{C}_{6}}{{H}_{5}}CHO\]do not undergo this reaction.
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