A) \[Al\]
B) \[P\]
C) \[Si\]
D) \[Mg\]
Correct Answer: B
Solution :
Ionization energy increase in a period from left to right due to decrease in size. But ionisation energy of \[IIA>IIIA\] \[VA>VIA\] (\[\because \]of stable electronic configuration) Thus, the correct order is \[Na<Al<Mg<Si<S<P<Cl\] Thus, among the given. P has maximum I.P.
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