A) glucose
B) fructose
C) glucose + fructose
D) laevulinic acid
Correct Answer: D
Solution :
Sucrose react with cone. \[HCl\] to form laevulinic acid. \[\underset{Sucrose}{\mathop{{{C}_{12}}{{H}_{22}}{{O}_{11}}}}\,\xrightarrow{cone.\,\,HCl}\underset{Laevulinic\,acid}{\mathop{C{{H}_{3}}COC{{H}_{2}}CHCOOH}}\,\] \[{{C}_{12}}{{H}_{22}}{{O}_{11}}\xrightarrow[Enzyme]{Inversion}\underset{Glu\cos e}{\mathop{{{C}_{6}}{{H}_{12}}{{O}_{6}}}}\,+\underset{Fructose}{\mathop{{{C}_{6}}{{H}_{12}}{{O}_{6}}}}\,\]
You need to login to perform this action.
You will be redirected in
3 sec
