A) very low value of 1st and II nd IE
B) very high value of 1st and II nd IE
C) high value of 1st IE and low value of II nd IE
D) low value of 1st IE and high value of II nd IE
Correct Answer: D
Solution :
\[Na(11)=1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{1}}\] It readily give one electron to attain stability, thus value of 1st IE is less \[N{{a}^{+}}=1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}\] 2nd electron has to be removed from complexly filled p orbital which require large amount of energy i.e., value of Und IE is very large which make it difficult to form \[N{{a}^{2+}}\] ion.
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