2. Solved Papers
  3. AIIMS

AIIMS AIIMS Solved Paper-2001

  • question_answer
    A spherical drop of water has 1 mm radius. If the surface tension of water is \[70\times {{10}^{-3}}\]N/m, then the difference of pressures between inside and outside of the spherical drop is:

    A)  \[140\,N/{{m}^{2}}\] 

    B)                         \[14\,N/{{m}^{2}}\]          

    C)             \[35\,N/{{m}^{2}}\]     

    D)                         none of these

    Correct Answer: A

    Solution :

                    Let the radius of drop be R, and surface tension of water be T, then the excess pressure or difference of pressure between inside and outside of the spherical drop is given by \[p=\frac{2T}{R}\] Given,     \[R=1mm=1\times {{10}^{-3}}m\] \[T=70\times {{10}^{-3}}N/m\] \[\therefore \]   \[P=\frac{2\times 70\times {{10}^{-3}}}{1\times {{10}^{-3}}}=140N/m\]


You need to login to perform this action.
You will be redirected in 3 sec spinner