A) 1.84M
B) 18.4 M
C) 20.6 M
D) 24.5 M
Correct Answer: B
Solution :
98% by mass means-98 g of \[{{H}_{2}}S{{O}_{4}}\] is present in 100 got acid. \[M=\frac{given\,mass\times 1000}{mol.\,mass\times V}\] Given, mass = 98 g Mol. mass = 98 g \[V=\frac{mass}{density}=\frac{100}{1.84}\] \[\because \] density of \[{{H}_{2}}S{{O}_{4}}\] is 1.84 g/cc Putting the values: \[M=\frac{98\times 1000\,\times 1.84}{98\times 100}\,=18.4\,M\]You need to login to perform this action.
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