A) 1.47 Hz
B) 0.36 Hz
C) 2.94 Hz
D) 2.48 Hz
Correct Answer: A
Solution :
Key Idea: Maximum displacement from mean occurs at \[\frac{T}{4}.\] For a motion in SHM particle taken one-fourth of periodic time to reach maximum displacement. Hence, periodic time is given by \[T=0.17\times 4=0.68s\] Hence, \[frequency=\frac{1}{time\,peroid}\] \[=\frac{1}{0.68}=1.47Hz\]You need to login to perform this action.
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