A) \[\frac{A{{\varepsilon }_{0}}({{k}_{1}}\times {{k}_{2}})}{d({{k}_{1}}+{{k}_{2}})}\]
B) \[\frac{A{{\varepsilon }_{0}}({{k}_{1}}-{{k}_{2}})}{d}\]
C) \[\frac{A{{\varepsilon }_{0}}{{k}_{1}}{{k}_{2}}}{({{k}_{1}}+{{k}_{2}})}\]
D) \[\frac{A{{\varepsilon }_{0}}({{k}_{1}}+{{k}_{2}})}{d}\]
Correct Answer: D
Solution :
Key Idea: In each capacitor the area of the plate will be A. In the given combination the arrangement is equivalent to two capacitors connected in parallel. Also in each capacitor the area of the plate will be \[\mu \]. \[\alpha \] Equivalent capacitance \[v=\omega \sqrt{{{a}^{2}}-{{x}^{2}}}\] \[\sqrt{g}\]
You need to login to perform this action.
You will be redirected in
3 sec
