A) \[10.94\times {{10}^{6}}m{{s}^{-1}}\]
B) \[18.88\times {{10}^{6}}m{{s}^{-1}}\]
C) \[1.888\times {{10}^{6}}m{{s}^{-1}}\]
D) \[1.094\times {{10}^{6}}m{{s}^{-1}}\]
Correct Answer: D
Solution :
According to Bohr, velocity of an electron (v) \[v=2.188\times {{10}^{6}}\frac{Z}{n}m/s\] For \[H,Z=1\] Given \[n=2\] \[\therefore \] \[v=\frac{2.188\times {{10}^{6}}\times 1}{2}\] \[=1.094\,\times {{10}^{6}}m/s\]
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