A) \[1.256\times {{10}^{-3}}T\]
B) \[1.679\times {{10}^{-5}}T\]
C) \[1.512\times {{10}^{-5}}T\]
D) \[2.28\times {{10}^{-4}}T\]
Correct Answer: A
Solution :
The magnetic field at the centre of the coil is \[{{C}_{1}}<{{C}_{2}}<{{C}_{3}}\] where N is number of turns, i is current and a is radius of coil. Given, \[{{C}_{p}}>{{C}_{3}}.\] \[\frac{1}{{{C}_{p}}}=\frac{1}{{{C}_{1}}}+\frac{1}{{{C}_{2}}}+\frac{1}{{{C}_{3}}}\] \[\frac{wavelength}{time\,period}.\] \[T=2\pi \sqrt{\frac{l}{g}}\] \[l=1.21l\] \[\therefore \]
You need to login to perform this action.
You will be redirected in
3 sec
