AIIMS AIIMS Solved Paper-2001

  • question_answer
    The oxidation number of \[Cr\] in \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\] is:          

    A)  \[+2\]                  

    B)  \[+4\]                  

    C)  \[+6\]                  

    D)         \[+7\]                  

    Correct Answer: C

    Solution :

    Let the oxidation number of \[Cr\] in \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\] be x oxidation number of \[O=-2;K=+1\] \[\therefore \]  \[2\times +1+2x+7\times -2=0\] \[2x=12\] \[x=+6\]


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