A) Nitrogen
B) Oxygen
C) Fluorine
D) Sulphur
Correct Answer: A
Solution :
Atomic number of element having electronic configuration \[1{{s}^{2}}2{{s}^{2}}2{{p}_{x}}^{1}{{p}_{y}}^{1}{{p}_{z}}^{1}\] is 7 and nitrogen has atomic number 7. \[\therefore \] it corresponds to N. Oxygen \[(8)=1{{s}^{2}}2{{s}^{2}}2{{p}_{x}}^{1}{{p}_{y}}^{1}{{p}_{z}}^{1}\] Fluorine \[(9)=1{{s}^{2}}2{{s}^{2}}2{{p}_{x}}^{2}{{p}_{y}}^{2}{{p}_{z}}^{1}\] Sulphur \[(16)=1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}_{x}}^{2}{{p}_{y}}^{1}{{p}_{z}}^{1}\]
You need to login to perform this action.
You will be redirected in
3 sec
