A) dil. \[KMn{{O}_{4}}\]
B) conc. \[{{H}_{2}}S{{O}_{4}}\]
C) \[AgN{{O}_{3}}\] in ammonia
D) \[B{{r}_{2}}\] in \[CC{{l}_{4}}\]
Correct Answer: C
Solution :
Propyne and propene can be distinguished by ammonia cal \[AgN{{O}_{3}}\] solution. Propyne give white ppt. with it while propene has no effect. \[R-C\equiv CH+[Ag{{(N{{H}_{3}})}_{2}}]OH\to \] \[\underset{\begin{smallmatrix} Silver\,alkylide \\ (white\,ppt.) \end{smallmatrix}}{\mathop{R-C\equiv C\,Ag\downarrow {{H}_{2}}O+N{{H}_{3}}}}\,\] Note: All terminal alkynes undergo this reaction. \[\underset{2-keto\,propanoic\,acis}{\mathop{\underset{\Pr opyne}{\mathop{C{{H}_{3}}C\equiv CH}}\,\xrightarrow[[O]]{Alk.\,KMn{{O}_{4}}}\,C{{H}_{3}}-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,-COOH}}\,\]You need to login to perform this action.
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