A) 10 W
B) 20 W
C) 40 W
D) 100 W
Correct Answer: A
Solution :
Power of bulb is given by \[{{k}_{1}}\] Supply voltage is 100 V and actual voltage is 200V \[{{F}_{1}}=-{{k}_{1}}{{y}_{1}}\] \[{{F}_{2}}=-{{k}_{2}}{{y}_{2}}\] \[{{k}_{2}}\] \[{{k}_{1}}\] \[{{k}_{2}}{{F}_{1}}+{{k}_{1}}{{F}_{2}}=-{{k}_{1}}{{k}_{2}}({{y}_{1}}+{{y}_{2}})=-{{k}_{1}}{{k}_{2}}y\] \[{{F}_{1}}={{F}_{2}}=F(say)\]You need to login to perform this action.
You will be redirected in
3 sec