A) 42.0kJ
B) 64.0kJ
C) 86.0kJ
D) 92.0kJ
Correct Answer: D
Solution :
When one mole of \[N{{H}_{3}}\] is formed from its constituent elements the enthalpy change \[=-46.0kJ\] Therefore when one mole of \[N{{H}_{3}}\] decompose to give its constituent elements enthalpy change \[=-46.0kJ\] \[\Rightarrow \] When 2 mole \[N{{H}_{3}}\] decompose, enthalpy change \[=2\times 46=92.0kJ\]You need to login to perform this action.
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