A) zero
B) 1
C) 2
D) 3
Correct Answer: D
Solution :
The scalar praduct of two vectors is given by \[\alpha =\frac{\Delta {{i}_{C}}}{\Delta {{i}_{g}}}\] where \[\Delta {{i}_{C}}\] is angle between them. Given, \[\Delta {{i}_{g}}\] \[\alpha =0.96,\Delta {{i}_{E}}=7.2,\] \[\Delta {{i}_{C}}=0.96\times 7.2=6.91mA\] \[\Delta {{i}_{E}}=\Delta {{i}_{C}}+\Delta {{i}_{B}}\] \[\therefore \] \[\Delta {{i}_{B}}=\Delta {{i}_{E}}-\Delta {{i}_{C}}\] \[=7.2-6.91=0.29mA\] \[\frac{(2n+1)\lambda }{2}\] Hence, positive value of a is 3.You need to login to perform this action.
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