A) \[\Rightarrow \]
B) \[{{m}_{1}}=1.5kg\]
C) \[{{k}_{1}}\]
D) \[{{y}_{1}}\]
Correct Answer: C
Solution :
Key Idea: No charge flows through capacitor \[{{u}_{1}}=1m/s=0.05kg,{{v}_{2}}=30m/s\]. The given network can be replaced through that shown below. This is a wheatstone bridge arrangement in which \[\Rightarrow \] Hence, bridge is balanced. No charge flows through \[{{m}_{1}}\times 1=0.05\times 30\], hence \[\Rightarrow \] is not considered. Capacitors \[{{m}_{1}}=1.5kg\] and \[{{k}_{1}}\] and in series \[{{y}_{1}}\] \[{{k}_{2}}\] \[{{y}_{2}}\] Also \[y={{y}_{1}}+{{y}_{2}}\] and \[{{k}_{1}}\] are in series, hence \[{{F}_{1}}=-{{k}_{1}}{{y}_{1}}\] Now, C and C" are in parallel, hence net capacitance between a and d is \[{{F}_{2}}=-{{k}_{2}}{{y}_{2}}\]You need to login to perform this action.
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