A) mass of die earth
B) mass of the projectile
C) radius of the projectiles orbit
D) gravitational constant
Correct Answer: B
Solution :
Key Idea: To leave the gravitational field of the earth, kinetic energy is equal to potential energy. At a certain velocity of projection, the body will go out of the gravitational field of the earth and will never return of the earth. This initial velocity is called escape velocity. The kinetic energy given to the body should be equal to potential energy for body to escape. i.e., potential energy = kinetic energy \[2:1\] where m is mass of projectile, \[1:2\] is mass of earth, G is gravitational constant, R is radius. \[{{m}^{-2}}{{s}^{-1}}\] \[{{m}^{-2}}{{s}^{-1}}\] The above formula shows that escape velocity is independent of the mass of the projectile. Note: Escape velocity is very Jess on moons surface.
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