A) \[x\]
B) \[{{i}_{1}},\]
C) zero
D) \[{{i}_{2}},\]
Correct Answer: C
Solution :
From Coulombs law, two stationary point charges \[2\mu F\] and \[{{T}_{2}}>{{T}_{1}}\] repel or attract each other with a force (F) which is directly proportional to the product of charges and inversely proportional to the square of distance (r) between them. \[3q/{{\varepsilon }_{0}}\] The various forces acting at charge +Q are: \[2q/{{\varepsilon }_{0}}\] force of attraction \[q/{{\varepsilon }_{0}}\] \[\beta \] is force of repulsion \[x\] Resolving the force, we have \[y\] along and \[x\]. Two equal and opposite forces which cancel each other. Hence, net force is zero.You need to login to perform this action.
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