A) 25km
B) 250km
C) 2500km
D) 5000km
Correct Answer: C
Solution :
Key Idea: Distance travelled by both the waves is same. Let the time taken by the S and P waves to reach the seismograph be \[y\] and \[x\] then \[{{i}_{1}},\] Since, 60s = 1 min \[{{h}^{1/2}}\] \[h\] Let distance of epicentre be s, then \[{{h}^{3/2}}\] \[{{h}^{2}}\] \[\beta \] \[[{{M}^{-1}}L{{T}^{-2}}A]\] \[[{{M}^{-2}}L{{T}^{-2}}{{A}^{-1}}]\] \[[ML{{T}^{-2}}{{A}^{-2}}]\] \[[ML{{T}^{-1}}{{A}^{-1}}]\] \[{{\beta }^{-}}\] \[+\frac{G{{M}_{e}}m}{R}=\frac{1}{2}mv_{e}^{2}\] \[{{M}_{e}}\] \[\therefore \] \[{{v}_{e}}=\sqrt{\frac{2G{{M}_{e}}}{{{\operatorname{R}}_{e}}}}\] \[P+\frac{1}{2}\rho {{v}^{2}}+\rho gh=constant\]
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