A) 2 MHz
B) 10 MHz
C) 12 MHz
D) 18 MHz
Correct Answer: A
Solution :
The perceived frequency of sky wave for reflection from an ionospheric layer is \[\frac{1}{2\pi }\sqrt{\frac{k}{m}}\] where n is the number density of electrons/ \[\frac{1}{2\pi }\sqrt{\frac{2k}{m}}\]. Given, \[\frac{1}{2\pi }\sqrt{\frac{3k}{m}}\] \[\therefore \] \[{{v}_{c}}=9\times {{({{10}^{11}})}^{\frac{1}{2}}}\] \[=2.8MHz\approx 2MHz\]
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