AIIMS AIIMS Solved Paper-2003

  • question_answer
    In the following common emitter configuration an n- p- n transistor with current gain \[\Omega \] -100 is used. The output voltage of the amplifier will be

    A)  10 mV  

    B)                                        0.1 V                    

    C)        1.0 V 

    D)        10 V    

    Correct Answer: C

    Solution :

             Current gain is defined as the ratio of collector current to base current, that is \[\beta =\frac{{{i}_{C}}}{{{i}_{B}}}=\frac{{{V}_{0}}}{{{V}_{i}}}\] where \[{{V}_{0}}\] is output voltage and \[{{V}_{i}}\] is input voltage. Given, \[\beta =100,{{V}_{i}}={{10}^{-2}}V\] \[\therefore \] \[{{V}_{0}}=\beta {{V}_{i}}=100\times {{10}^{-2}}=1V\] Note: In common-emitter mode, the input and output signals are in opposite phase, while in the common-base mode, the output and input signals are in same phase.


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