A) \[N{{a}_{3}}V{{O}_{4}}\]
B) \[[V{{({{H}_{2}}O)}_{6}}]S{{O}_{4}}.{{H}_{2}}O\]
C) \[MnO_{4}^{2-}\]
D) \[MnO_{4}^{-}\]
Correct Answer: C
Solution :
\[COC{{H}_{3}}\]and \[NHCOC{{H}_{3}}\] all are tetrahedral in shape but \[C{{H}_{3}}{{O}^{-}}\] is not-tetrahedral but square planar
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