A) \[Mn{{O}_{2}}\]
B) \[M{{n}_{2}}{{O}_{7}}\]
C) \[Mn{{O}_{2}}\]
D) \[+II\]
Correct Answer: C
Solution :
Species which have incompletely filled d-orbitals form coloured compounds whereas species with completely filled or vacant d orbitals are colourless. \[{{(C{{H}_{3}})}_{2}}CH{{O}^{-}}\] (coloured) \[{{(C{{H}_{3}})}_{3}}C{{O}^{-}}\] \[C{{H}_{3}}C{{O}_{2}}C{{H}_{3}}\] (coloured) \[C{{H}_{3}}C{{O}_{2}}{{C}_{2}}{{H}_{5}}\] \[{{C}_{6}}{{H}_{5}}C{{O}_{2}}C{{H}_{3}}\] (colourless) \[C{{H}_{3}}C{{O}_{2}}{{C}_{6}}{{H}_{5}}\] \[Sn/HCl\]= coloured
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