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AIIMS AIIMS Solved Paper-2003

  • question_answer
    Lanthanide for which \[NOCl\] and \[NC{{l}_{3}}\] oxidation states are common is:

    A)  \[{{N}_{2}}{{O}_{4}}\]                                  

    B)  \[N{{H}_{3}}\]                 

    C)  \[N{{a}^{+}}\]                  

    D)         \[N{{H}_{3}}\]

    Correct Answer: D

    Solution :

    Lanthanoids are/-block elements starting from \[C{{H}_{3}}Cl,C{{H}_{3}}Br,C{{H}_{3}}F\] to \[C{{H}_{3}}F,C{{H}_{3}}Cl,C{{H}_{3}}Br\]
    Elements Atomic no. Oxidation state
    \[C{{H}_{3}}Br,C{{H}_{3}}Cl,C{{H}_{3}}F\] \[C{{H}_{3}}Br,C{{H}_{3}}F,C{{H}_{3}}Cl\] \[N{{a}_{2}}O\]
    \[C-H\] \[N{{H}_{4}}N{{O}_{3}}\] \[N{{H}_{4}}N{{O}_{3}}\]
    \[-7.53\text{ }kJ/mol\] \[-398.1\text{ }kJ/mol\] \[-16.1\text{ }kJ/mol\]
    \[-602\text{ }kJ/mol\] \[Cd(s)+2Ni{{(OH)}_{3}}(s)\xrightarrow{{}}CdO(s)\] \[+2Ni{{(OH)}_{2}}(s)+{{H}_{2}}O(l)\]
    Thus for \[Pb(s)+Pb{{O}_{2}}(s)+2{{H}_{2}}S{{O}_{4}}(aq)\xrightarrow{{}}\] common oxidation states are \[2PbS{{O}_{4}}(s)+2{{H}_{2}}O(l)\] and \[2{{H}_{2}}(g)+{{O}_{2}}(g)\xrightarrow{{}}2{{H}_{2}}O(l)\].


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