A) \[COC{{H}_{3}}\]
B) \[NHCOC{{H}_{3}}\]
C) \[C{{H}_{3}}{{O}^{-}}\]
D) \[{{C}_{6}}{{H}_{5}}{{O}^{-}}\]
Correct Answer: B
Solution :
\[[V{{({{H}_{2}}O)}_{6}}]S{{O}_{4}}.{{H}_{2}}O\] is strongest acid In \[MnO_{4}^{2-}\] and\[MnO_{4}^{-}\] the \[Mn{{O}_{2}}\] group being electron donating make benzoic acid weaker.
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