A) \[N{{a}_{2}}O\]
B) \[C-H\] followed by \[N{{H}_{4}}N{{O}_{3}}\]
C) \[N{{H}_{4}}N{{O}_{3}}\], followed by \[-7.53\text{ }kJ/mol\]
D) \[-398.1\text{ }kJ/mol\]
Correct Answer: C
Solution :
Propanol-1 can be prepared from propene as follows \[S{{O}_{2}}\] \[C{{H}_{3}}COOH\] \[{{C}_{6}}{{H}_{5}}COOH\] (This addition follow Markownikoffs rule) But in the presence of peroxide we obtain 1- propanol. \[m-C{{H}_{3}}O{{C}_{6}}{{H}_{4}}COOH\] (Anti-Markownikoff addition)
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