A) 2.5
B) 5
C) 10
D) 20
Correct Answer: C
Solution :
From Rutherford and Soddy law for radioactive decay \[{{i}_{2}},\] where \[{{h}^{1/2}}\] and N are number of atom in a radioactive substance at time t = 0 and t =t and \[h\] is decay constant. Also, half-life \[{{h}^{3/2}}\] \[{{h}^{2}}\] \[\frac{N}{{{N}_{0}}}\,={{e}^{\frac{0.693}{{{T}^{1/2}}}t}}\] Given, \[[{{M}^{-1}}L{{T}^{-2}}A]\]days, \[[{{M}^{-2}}L{{T}^{-2}}{{A}^{-1}}]\] \[[ML{{T}^{-2}}{{A}^{-2}}]\] \[[ML{{T}^{-1}}{{A}^{-1}}]\] \[{{\beta }^{-}}\] \[+\frac{G{{M}_{e}}m}{R}=\frac{1}{2}mv_{e}^{2}\] \[{{M}_{e}}\] \[\therefore \] days.
You need to login to perform this action.
You will be redirected in
3 sec
